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dy 2x2 + 3y2 1. Solve the initial value problem y(-1) = -V3 by first making a dac ту substitution. Write your solution y(x) a

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Answer #1

Let y = vx.

then, differentiating with respect to x, we get,

= 1 +X- dy dv dx dx Plugging these values in the given differential equation, dv_2x² +3(vx)? 2x2 + 3y2x2 2 = - + 3V dh x(1x)

1 - V3 =-1/C(+1)* - 1 Given: y(-1) = -V3 3=C-1 Hence, y=xV4x4 - 1 C=4 This solution is valid when 4x4 -1>0 or 4x4> 1 Ol 14 4


answered by: ANURANJAN SARSAM
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