[python] Write a method that given a heap array returns the second smallest element in a heap.
import sys
def print2Smallest(arr):
# There should be atleast two elements
arr_size = len(arr)
if arr_size < 2:
print "Invalid Input"
return
first = second = sys.maxint
for i in range(0, arr_size):
# If current element is smaller than first then
# update both first and second
if arr[i] < first:
second = first
first = arr[i]
# If arr[i] is in between first and second then
# update second
elif (arr[i] < second and arr[i] != first):
second = arr[i];
if (second == sys.maxint):
print "No second smallest element"
else:
print ' second smallest element is',second
arr = [12, 13, 1, 10, 34, 1]
print2Smallest(arr)
The above code is efficient in finding the second smallest element and the first smallest element in the heap array.
Can also be done using extract-min for the heap 2 times. it will take o(1) time.
[python] Write a method that given a heap array returns the second smallest element in a...
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