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The analysis of a coal indicates 75wt% C, 17% H, 2% S, the balance noncombustible ash....

The analysis of a coal indicates 75wt% C, 17% H, 2% S, the balance noncombustible ash. The coal is burned at a rate of 5000 kg/h, and the feed rate of air to the furnace is 50 kmol/min. All of the ash and 6% of the carbon in the fuel leave the furnace as a molten slag; the remainder of the carbon leaves in the stack gas as CO and CO2; the hydrogen in the coal is oxidized to water, and the sulfur emerges as SO2. The selectivity of CO2 to CO production is 10:1. a) Calculate the percent excess air fed to the reactor. b). Calculate the mole fractions of the gaseous pollutants – CO and SO2 – in the stack gas.

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Answer #1

of c 12,5 Components 75 wt% 17% H 2% coal 0.75X5000 = 3 12,5 kmol/h 0.17 85000 = 850 umol/h 0.0245o0o = 3.125 kmollh X 5000 1Carbon reacted = (1-0.06)* 312.5 = 293.75 kmelthe CO2 formed - Ox 293,75 =267.045 kinel/h co formed = 293.75 = 26. 7045 kmollexcess O, supplied - On supplied stred - — Orthoritical x100 XIDO This surelied - Oz theoritical 630 293.75 2x100 293.75 #114le consumed for co, for co -s for so. ~ for Ho 267.045 kmol/ha ty 26,7045= 13.35225 kr 3.125 kmollhr 0,5% 425=212.5 kmollhr V

answered by: ANURANJAN SARSAM
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