KE1 + PE1 = KE2 + PE2
0 + 7.40*9.8*5.20 = 1/2*7.40*V^2 + 7.40*9.8*3.20
=> VB = 6.26 m/s
0 + 7.40*9.8*5.20 = 1/2*7.40*V^2 + 7.40*9.8*2
=> VC = 7.91 m/s
b) work = F*X = 7.40*9.8*3 = 232 J
A block of mass m = 7.40 kg is released from rest from point and slides...
8.2
A block of mass m = 5.10 kg is released from rest from
point and slides on the
frictionless track shown in the figure below. (Let
ha = 7.40 m.)
(a) Determine the block's speed at points and .
vB
= m/s
vC
= m/s
(b) Determine the net work done by the gravitational force on the
block as it moves from point to point
.
J
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