3. (16 points) Solve the system of linear congruences using the Chinese Remainder Theorem. 4 (mod...
9. Use the construction in the proof of the Chinese remainder theorem to find a solution to the system of congruences X 1 mod 2 x 2 mod 3 x 3 mod 5 x 4 mod 11 10. Use Fermats little theorem to find 712 mod 13 11. What sequence of pseudorandom numbers is generated using the linear congruential generator Xn+1 (4xn + 1) mod 7 with seed xo 3? 9. Use the construction in the proof of the Chinese...
5. (20 points) Solve the system of congruences x (mod 13) and 11 (mod 24). Find the smallest nonnegative integer solution to the system.
A) If possible, solve the following system of congruences using either of the two methods of this section. x ≡ 4 (mod 11) x ≡ 3 (mod 17) x ≡ 6 (mod 18) B) Find the inverse of 19 modulo 23. Show all steps taken in neat English to receive a positive review
Solve the system of linear congruences: 7x = 1 mod 8, 7x = 1 mod 13, 7x = 1 mod 17
In the following, the moduli are not pairwise relatively prime, so the Chinese Remainder Theorem does not apply immediately. First reduce it to a system with relatively prime moduli and then solve it. 7 (mod 12) =13 (mod 18)
Problem 1 Use the Chinese remainder theorem, find all integers x such that: (20 pts) x = 1 (mod 5) x = 2 (mod 7) x = 3 (mod 9) x = 4 (mod 11)
(3) Solve the following linear congruence: 271 = 12 mod 39. (4) Solve the following set of simultaneous linear congruences: 3x = 6 mod 11, x = 5 mod 7 and 2x = 3 mod 15.
Problem 1 Use the Chinese remainder theorem, find all integers x such that: (20 pts) x = 1 (mod 5) r = 2 (mod 7) x = 3 (mod 9) I= 4 mod 11) Answer,
Arrange the steps in the correct order to solve the system of congruences x 2 (mod 3), x 1 mod 4). and x3 (mod 5) using the method of back substitution Rank the options below Thus, x= 31.2 - 3/4 + 1)2 - 120+5 We substitute this into the third congruence to obtain 12.5 13 mod 5), which implesu li imod 5) Hence, w5v4 and so x 12.5 - 12/5 + 4) - 5 - 60v. 53, where vis an...
(d) Decrypt the ciphertext message LEWLYPLUJL PZ H NYLHA ALHJOLY that was encrypted with the shift cipher f(p) (p+7) mod 26. [10 points] (e) [Extra Credit - 5 points] Encrypt the message "BA" using the RSA cryptosystem with key (ne) = (35,5), where n = p . q 5-7 and ged(e, (p-1) 1)) (5, 24) 1. 6. [5 points each (a) Is 2 a primitive root of 11? (b) Find the discrete logarithm of 3 modulo 11 to the base...