Question

3. (16 points) Solve the system of linear congruences using the Chinese Remainder Theorem. 4 (mod 11) a 11 (mod 12) x=0 (mod
b. (6 pts) Find the inverses n (mod 11), n21 (mod 12), and nz1 (mod 13). Using these ingredients find the common solution a (
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Answer #1

( med ly Constan k, 13 M omo mod 13 几 131 13 リソソ l 2. 2 heu -r- at , t / ba2 s lr/ @gn. イ ぐぐ-1 0111 it ha us inve mod 2 12 ned 1

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3. (16 points) Solve the system of linear congruences using the Chinese Remainder Theorem. 4 (mod...
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