Question

S m 6. (19 points) A projectile of mass m= 2.00kg is fired at an asteroid of mass M = 400kg at a speed of vo = 1000 in the direction shown. The asteroid breaks into two pieces, m = 100kg and m2 = 300kg. The final speeds of the asteroid pieces are v, =10.00 and v, = 5.00 in the S directions shown. What are the final speed and direction of the velocity of the projectile after the collision? (Note: The projectile has not been drawn in the "after" picture of the diagram but must be included.) S Before After 15° m M m' 835

Answer 1

projectile mass mass (m) = 2 kg Asteroid mess (m) =400 by projectile velocity ( )= 1000 m After collision projectile speed = V mls. Asteroid initial velocity(v) = 0 o mis Asteroid pieces moss (m)=10069, velocity (V, 2= lomls mass (m) =300 kg, velocity (V 2 =5 mls . Before Aftes v or is vo y a 3 mo smo To ܐܘ

conserve linear momentum along x. along x-direction moyo & MO? mo v coso ut m Vico Ces ) + m₂ ces (35) 2 2x.1000 + 400(0) = m vcgo + 100 xrocos(es) 300x cos(35 + mo V COSO - -194.653827 -19.4-65 3827 V COTO = -97032694636 mis linear conserve momentem y-direction: along O = my sin (is) + mv sin(o)-mv my sin(35) in v sine m ve sin (35)-mv sin (is) 300 XS X sin ( 307 )- 100X10 X sincus.) mv sino 601.5456094 60 los456094 w.sino 2 300.7728047 mls V sino a

v final speed magnitud v (versos +(usinoj Vs fa7-32694636) + 300.77280 28047) va 316.13 mil's Direction : vsing vsino o=font 3 ] V COJO Vceso 30007728047 o = Tan 97-32694636 7 2006 En reverse direction Afler collision Y A Jis. 3.6.