Question

Two bars are connected through a spring as shown in Figure. Left end of the left bar is restrained by a spring. Determine axial forces in the bars and the springs. The right end of the assembly is fixed. There is a uniformly distributed axial load 100N/m applied on the left bar. A concentrated load Pis applied at the free end of the right bar. Divide the left bar into two equal length elements and right bar into one element. Use the following numerical data. P 00 load 100 Nm 2.5 m 2 m

Determine:

a)the force in the left spring

b)the force in the middle spring

c)the axial force in the left half of the left bar

d)the axial force in the right half of the left bar

e)the axial force in the right bar

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Answer #1

given KI ake P man Eye 1 K * 11.25m 1.25m am I Hosizontal force o IE= 2008 109 Nint A = 100 m² 104Nlm 100x 2-5 tp - RA- Rro09 deformation on change in length ) of BC OoNlm (RA-125) N 11.25m i fx = RA-(100xx)N fie da CRA - 1000) da AE 1.25 (Rn - 100+0.58109 CRA- 250) + 5x108 (2RA-500) = 5x108 (1.25 RA-156.25 - 78.126) CAL = 5x108 (1125RA-234.375) 17 -10 RA force - ALK ALRA 46.25810 2500X10 8 RA - 390.625x108 + 6.25x16 - 1141.875X108 + 0.56164 RA - 125x104 + 10x108R RA +0.5x104 = RA Crow +6.25xRA-125 = – 41.52106N RA - RA- 125 = 41.52106 N The orial force in the right half of the ban RA-250 83.4Agru-200 Ro-12 -1bf. 1

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