Question

Find an equation of the tangent plane to the given surface at the specified point. z = ln(x − 6y), (7, 1, 0)

Answer 1

Z - In i 2-6y) Dibt ego partially wor. ton е xe en ra-by) aa Za ༣ - -6y at point 17,0,0) 2x - 1 7-611) 22 1 = Wiggi toy e he - Diff ean partially az en (x-oy ) ay (-6) zy 2-64 at (7,00 zy 7-611) -6 N. E-6 zy

curve za tangent plane eros yos rs at fix,y) be given then egn of at point zo) =(x-7.) 5*(x0,40,20 ) + Cay-Yo 0 #f180, Yop 20) 노 20) 1 ds YOO zoo Here Xos 617,0,0) = ln (7-6) = enco) - O Eqa of tangent plane is Z = (-7) 61) + CY-1)(-6) +o z = 2-7-6y +6 z =2-6y-11 Z