Question 21 0/4 pts What is the entropy change of the surroundings when the reaction below...

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Answer 1

Answer #1

The given reaction is

$C(graphite)+2H_{2}(g)\rightarrow CH_{4}(g)$

Under standard conditions at 298 K ,

The Standard Enthalpy Change of the reaction , $\Delta H^{0}=-74.9KJ$

The Standard Entropy Change of the reaction system is , $\Delta S_{sys}^{0}=\frac{\Delta H^{0}}{T}$

$\Delta S_{sys}^{0}=\frac{-74.9*10^{3}J}{298K}\approx -251.34JK^{-1}$

Also , for a reversible reaction at equilibrium , $\Delta S_{sys}^{0}=-\Delta S_{surr}^{0}$

$\Delta S_{surr}^{0}=251.34JK^{-1}$

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Answer 2

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