HESSAGE HY INSTRUCTOR Chapter 06, Problem 069 SN Р Р of magnitude and angle A student,...

Question

Question

Answer 1

Answer #1

Solution:

. Fg = m*g

Fn= P*Sin(theta) - Fg = P*Sin(theta) - m*g

Now, fk = uk * Fn = uk*[P*Sin(theta) - m*g]

Now,

F = P*Cos(theta) - fk

Or,F = P*Cos(theta) - uk*[P*Sin(theta) - m*g]

Therefore, Accelaration of Block = a = F/m = (1/m)[P*Cos(theta) - uk*{P*Sin(theta) - m*g}]

Answer 2

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