Consider the first order separable equation y(1 + 53*) 1/3 An implicit general solution can be...
(1 point) Consider the first order separable equation y = 16xy(1+2x51/3 An Implicit general solution can be written in the form y = Cf(x) for some function f(x) with C an arbitrary constant. Here f(x) e (1+2x^6)^(4/3) Next find the explicit solution of the initial value problem y(0) = 5
sef (1 point) Consider the first order separable equation y' = 45x®y(1 +520)1/2 An explicit general solution can be written in the form y=Cf(x) for some function f(x) with Can arbitrary constant. Here f(x) = Next find the explicit solution of the initial value problem y(0) = 1 y=
(1 point) Consider the first order separable equation y' y(y- 1) An implicit general solution can be written in the form e + h(x, y) Find an explicit solution of the initial value problem y(0)3 C where h(z, y) ( y)
2.rezy (15 points) Consider the first order separable equation y An implicit general solution can be written in the form ey +C Find an explicit solution of the initial value problem y(0) = 1 y=
(1 point) The equation 3ry2r 2y2 (*) can be written in the form y f(y/x), ie., it is homogeneous, so we can use the substitution u = y/x to obtain a separable equation with dependent variable uu(x. Introducing this substitution and using the fact that y' ru' u we can write () as y xu'w = f(u) where f(u) Separating variables we can write the equation in the form da np (n)6 where g(u) = An implicit general solution with...
A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor u(x) = exp c) dx (1) Given the equation y 2xy = 10x find H(x) = (2) Then find an explicit general solution with arbitrary constant C у %3 (3) Then solve the initial value problem with y(0) = 3 A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor...
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp ( (1) Given the equation y, +-= 7x4 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(1) = 2
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp (1) Given the equation y' + 2y = 2 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(0) 2
(1 point) A first order linear equation in the form y' + p(x) = f(x) can be solved by finding an integrating factor (1) exp(/ pla) de) (1) Given the equation ay' + (1 + 2x) y = 8e 22 find (x) (2) Then find an explicit general solution with arbitrary constant C (3) Then solve the initial value problem with y(1) - ?
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor u(x) = expl (1) Given the equation xy' + (1 +4x) y = 10xe 4* find y(x) = (2) Then find an explicit general solution with arbitrary constant C. y = (3) Then solve the initial value problem with y(1) = e-4 y =