Question

11. The electron configuration of phosphide ion (13-) is -- a) (Ne]3s 3p b) (Ne]3:43 d) [Ne3 e) (Ne]3s 3p c) Ne]3s 2. Which of the following atoms would be expected to have the largest electron affinity, or wou release the greatest amount of energy when an electron is added? 1) Na - 6 F c o d) Li d) LIB The halogens, alkali metals, and alkaline earth metals have ---------valence electrons, respectively a) 7. I. and 2 b) 8.2 and 3 c) 2.7 and 4 d) 2.4, and 6 e) 1,5. and 7

Answer 1

11. E

P : 15 atomic number (15 electron  

P3- : 18 electron

= [Ne] 3s2 3p6

12. B... Fluorine . F

F: 1s2 2s2 2p5

Electron affinity is the amount of energy released when an isolated gaseous atom accepts an electron.

since, fluorine already has 7 electrons in its valence shell. therefore, it will easily accept one electron to attain noble gas configuration.

Hence , most amount of energy will be released. therefore fluorine will have most negative electron gain enthalpy.

13. A

Halogens : ns2 np5 = 7 electron

Alkali metal : ns1 = 1 electron

Alkaline earth metals : ns2 = 2 electron