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pls help a b and c
te the 5th degree aclaurin pol sin(x). Show your Taylkor polyia 1114 31 5 (a) Use Taylors Remainder Theorem to express the r
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Answer #1

e(a) A Maclaurin series is given by f (z) k! in our case, f (x) P () - k! So, what we need to do to get the desired polynomia

Evaluate the 5th derivative at the given point: (f (0))(5) 1 Now use the calculated values to get a polynomial: 0, -1 2! 1! 5

Since sinx i )ว่า (C)少 Scanned with CamScannerSin 4 x + 120 -2 10 -8 -6 -2 2 2t

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