There is a abg with 62 tickets.31 and blue and 31 are red.ln 20 pulls from...

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There is a abg with 62 tickets.31 and blue and 31 are red.ln 20 pulls from...

There is a abg with 62 tickets.31 and blue and 31 are red.ln 20 pulls from the bag,20 tickets are red.What is the probabiltity with replacement that the 21st pull will be red?

a. .5000

b. .2500

c. 000000477

d. .03125

e. none of the above

math Statistics-And-Probability

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Answer 1

Answer #1

Since tickets are pulled with replacement hence each time a pull is made from the bag, there are total 62 tickets with 31 blue and 31 red. Hence prob of pulling red will be same for each pull independent of previous pulls.

P(red in 21st pull) = red tickets / total tickets = 31/62 = 0.5

Correct option A

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Answer 2

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