Given the input sequence 4371, 1323, 6173, 4199, 4344, 9679, 1989, a hash table of size b=10, and a hash function h(x)=x mod b, show each step needed to build a hash table
A closed hash table using double hashing, with the second hash function as
h′(x)=7 − (x mod 7)
This yields the sequence of hash functions
hi(x)=(x mod b + i⋅ (7 − ( x mod 7)))mod b for i=0,1,…
Given the input sequence 4371, 1323, 6173, 4199, 4344, 9679, 1989, a hash table of size...
Given input {4371, 1323, 6173, 4199, 4344, 9679, 1989} and a hash function h(x) = x (mod () 10), show the resulting: a. Separate chaining hash table b. Hash table using linear probing c. Hash table using quadratic probing d. Hash table with second hash function h2(x) = 7 - (x mod 7) *Assume the table size is 10.
Let 'M' denote the hash table size. Consider the following four different hash table implementations: a. Implementation (I) uses chaining, and the hash function is hash(x)x mod M. Assume that this implementation maintains a sorted list of the elements (from biggest to smallest) for each chain. b. Implementation (II) uses open addressing by Linear probing, and the hash function is ht(x) - (hash(x) + f(i)) mod M, where hash(x)x mod M, and f(i)- c. Implementation (III) uses open addressing by...
5. Hashing (a) Consider a hash table with separate chaining of size M = 5 and the hash function h(x) = x mod 5. i. (1) Pick 8 random numbers in the range of 10 to 99 and write the numbers in the picked sequence. Marks will only be given for proper random numbers (e.g., 11, 12, 13, 14 ... or 10, 20, 30, 40, .. are not acceptable random sequences). ii. (2) Draw a sketch of the hash table...
Double hashing is scheme for resolving collisions that uses two hash functions HCk, m) and hCk,m). It is similar to linear hashing except that instead of changing the index by 1, the value of the second hash function is used From the view of the general scheme, the Io(k, mHCk, m) Hi(k, m) -(H(k, m)+ h(k,m)) mod m H2 (k, m) = (H(k, m)+ 2 h(k,m)) mod m hash functions are. Hi (k, m) (H(k , m)+ h(k , m))...
Part 5. Suppose that your hash function resolves collisions using the open addressing method with double hashing. The double hashing method uses two hash functions h and h'. Assume that the table size N = 13, h(k) = k mod 13, h'(k) = 1 + (k mod 11), and the current content of the hash table is: 0 1 2 3 6 7 8 9 10 11 12 4 17 5 98 If you insert k = 14 to this...
3. Given input (89, 18, 49, 58, 69), h)k(mod 10) g) Iymod 8), and a hash function f(k) h(k) +j-g(k) (mod 10), show the resulting hash table. Solve collisions with double hashing. 3. Given input (89, 18, 49, 58, 69), h)k(mod 10) g) Iymod 8), and a hash function f(k) h(k) +j-g(k) (mod 10), show the resulting hash table. Solve collisions with double hashing.
11. Dra The size The hash function used is: the contents of the 13 hash tables below. Show your work for partial r hash table is HOk)-k mod 7 13, 17, 6, 24, 3 a) Resolve collisions with chaining b) Double hashing, where W20)-7-0mod 5) 0 1 1 2 2 3 3 4 4 5 5 6 6 c) What is the load factor for the table a? d) What is the load factor for the table b? f) Is...
Suppose we are inserting strings into a hash table of size 9. Suppose we have two hash functions, h, and h2. The hash values for certain strings of these functions are shown in the table below: Fill in the hash table below assuming that we are using open-address, linear-probing style hashing, given that the table starts as it appears below, the hash function is h_1 and the order of insertion is "Fred", "Chloe", "Adam", "Rebecca" and "Reggie". Fill in the...
10. Submission In this question you will work with a hash table that uses double hashing. The hash table is size 11, the primary hash function is h(K)-K mod 11, and the secondary hash function is hp(K)-(K mod9) +1 Take an empty hash table. Take your student number and split it into 4 2-digit integers. Insert each of these 2-digit numbers in the order in which they appear in your student number into the empty heap. Then insert the values...
6. A hash table has size 7, uses quadratic probing (f(i) = 1), and has hash function h(2) = 2%7. (Recall, % is the Java "mod" function.) Draw the contents of the hash table after the following sequence of insertions: insert 0, insert 7, insert 14, insert 21. The hash table is initially empty.