"Flip a Coin!"
You will write a program that allows the user to simulate a coin flip.
Note the following line of code: (Math.random()*2) +1;
This line generates a random number (a float) between 1 and 2. If you wanted to simulate somebody rolling a die, you could store the value of this variable as:
var coinFlip = (Math.random()*2) +1;
(Be sure to include all the parentheses in this line of code.)
Reminder - Of course, you’ll need to convert this to an integer…..
Have a button that says: "Flip the Coin!"
If the coin flip is a 1, then output "Heads". If the coin flip is a 2, then output 'Tails". Use a basic if-else block for this. (Do not use two separate if statements).
You can output the result to an alert box.
Writing the code in C as given you need if else blocks in the progarm
#include<stdio.h>
#include<math.h>
int main()
{
int choice = (int) (Math.random() * 2) + 1;
// Math. random will generate random float value between 0 and 1, hence the function will return random float value between 0 and 2, when type casted to int, it will return either 0 or 1
if(choice==1)
printf("Heads\n");
window.alert(Heads);
else
printf("Tails\n");
window.alert(Tails);
return 0;
}
"Flip a Coin!" You will write a program that allows the user to simulate a coin...
Simulate the flipping of a coin Print the result of the coin flip : use off numbers for Heads . and even numbers for Tails Update the number of times the result is Heads Update the number of times the coin has been flipped struct coin_prob{ int heads; int flips; }; void coin_flip(struct coin_prob * coin); You may use a rand functioon (assume its already been seeded), but no other pre-defined function
If you flip a coin and roll a die at the same time, what is
the probability of rolling a 5 or 6 and the coin showing
heads?
Question 3 Unanswered If you flip a coin and roll a die at the same time, what is the probability of rolling a 5 or 6 and the coin showing heads? (answer to 4 decimal places) Type your response
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