Homework Answers
A 0.5-0.9 %(m/v) solution of NaCl is isotonic to blood cells.So, a 1.5%(m/v) solution of NaCl is more concentrated, so water will move from the cells to the solution.So, a hypertonic solution is formed.
So, answer is A.
A 0.5-0.9 %(m/v) solution of NaCl is isotonic to blood cells.So, a 1.5%(m/v) solution of NaCl is more concentrated, so water will move from the cells to the solution.So, a hypertonic solution is formed.
So, answer is A.
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Question 17 Status: Not yet answered Points possible: 1.00 When blood cells are placed in a...
When blood cells are placed in a 0.50% (m/v) solution of NaCl, this is considered: crenation...
When blood cells are placed in a 0.50% (m/v) solution of NaCl, this is considered: crenation isotonic hypotonic hypertonic Question 19 (4 points) Saved When blood cells are placed in a 0.9% (m/v) solution of NaCl, this is considered: isotonic hemolysis hypotonic crenation
Hemolysis of red blood cells occurs when the cells are placed in ain) isotonic solution hypertonic...
Hemolysis of red blood cells occurs when the cells are placed in ain) isotonic solution hypertonic solution hypotonic solution physiological saline solution
Question 4 Status: Not yet answered | Points possible: 1.00 Suppose you are titrating an acid...
Question 4 Status: Not yet answered | Points possible: 1.00 Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 2.86 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 21.17 mL. What volume, in mL, of base was required for the titration? Type answer: Question 6 Status: Not yet answered Points possible: 1.00 Suppose you are...
Question 3 Status: Not yet answered | Points possible: 1.00 If 0.75 g of a monoprotic...
Question 3 Status: Not yet answered | Points possible: 1.00 If 0.75 g of a monoprotic weak acid required 22.50 mL of 0.510 M NaOH to titrate it, what is the molar mass of the acid? Select one: O 86 g/mol O 51 g/mol O 33 g/mol O 65 g/mol O 153 g/mol
Question 1 Status: Not yet answered | Points possible: 1.00 Which property is the basis of the purification techn...
Question 1 Status: Not yet answered | Points possible: 1.00 Which property is the basis of the purification technique recrystallization? Select one: Molecular weight O Polarity O Color Solubility We were unable to transcribe this imageQuestion 3 Status: Not yet answered Points possible: 1.00 What statements are always true about limiting reactants? Select one or more: There will be an excess of other reactants at the end of the reaction, The limiting reactant is completely used up in the reaction....
Question 3 Status: Not yet answered Points possible: 1.00 The rearrangement of pinacol occurs in the...
Question 3 Status: Not yet answered Points possible: 1.00 The rearrangement of pinacol occurs in the cation intermediate after losing water as a leaving group. The cation is originally located on the carbon Choose... However, the cation is more stable on the carbon Choose... Therefore, the rearrangement is Choose... from one carbon to another to create Choose... Question 3 Status: Not yet answered I Points possible: 1.00 The rearrangement of pinacol occurs in the cation intermediate after losing water as...
A 1.1%(m/v) solution of potassium chloride is isotonic with red blood cells. A). is a 0.11M...
A 1.1%(m/v) solution of potassium chloride is isotonic with red blood cells. A). is a 0.11M solution of potassium chloride hypotonic, isotonic, or hypertonic with red blood cells? convert the 0.11M potassium chloride solution concentration into % (m/v) to support your answer? please show every step. B). what would happen to the red blood cell immersed in a 0.11M potassium chloride solution- nothing, crenation, hemolysis?
Help me get the correct answers for the pictures and the question at the bottom. Cell...
Help me get the correct answers for the pictures and the
question at the bottom.
Cell membranes are semipermeable, and osmosis is an ongoing process in the body. Differences in osmotic pressure inside and outside a red blood cell can result in crenation (shriveling) or hemolysis (rupture). The diagram shows three solutions: an isotonic solution, a hypertonic solution, and a hypotonic solution. Place the appropriate red blood cell in each solution. isotonic solution hypertonic solution hypotonic solution Answer Bank The...
Question 1 Status: Not yet answered I Points possible: 1.00 Consider the reaction corresponding to a...
Question 1 Status: Not yet answered I Points possible: 1.00 Consider the reaction corresponding to a voltaic cell and its standard cell potential. Zn(s) + Cu²+ (aq) + Cu(s) + Zn2+ (aq) EO 'cell 1.1032 V What is the cell potential for a cell with a 2.823 M solution of Zn²+ (aq) and 0.1032 M solution of Cu2+ (aq) at 427.9 K?
Question 8 Status: Not yet answered Points possible: 1.00 During a recrystallization, the goal is to...
Question 8 Status: Not yet answered Points possible: 1.00 During a recrystallization, the goal is to form purified crystals of a solid out of solution. However, you might form an oil instead. How should you respond if an oil forms during your recrystallization? Select one: O Filter the mixture to remove the oil and continue with the recrystallization. O Use a separatory funnel and additional solvent to isolate the oil product. O Add more of the recrystallization solvent to form...
When blood cells are placed in a 0.50% (m/v) solution of NaCl, this is considered: crenation isotonic hypotonic hypertonic Question 19 (4 points) Saved When blood cells are placed in a 0.9% (m/v) solution of NaCl, this is considered: isotonic hemolysis hypotonic crenation
Hemolysis of red blood cells occurs when the cells are placed in ain) isotonic solution hypertonic solution hypotonic solution physiological saline solution
Question 4 Status: Not yet answered | Points possible: 1.00 Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read the base titrant volume as 2.86 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 21.17 mL. What volume, in mL, of base was required for the titration? Type answer: Question 6 Status: Not yet answered Points possible: 1.00 Suppose you are...
Question 3 Status: Not yet answered | Points possible: 1.00 If 0.75 g of a monoprotic weak acid required 22.50 mL of 0.510 M NaOH to titrate it, what is the molar mass of the acid? Select one: O 86 g/mol O 51 g/mol O 33 g/mol O 65 g/mol O 153 g/mol
Question 1 Status: Not yet answered | Points possible: 1.00 Which property is the basis of the purification technique recrystallization? Select one: Molecular weight O Polarity O Color Solubility We were unable to transcribe this imageQuestion 3 Status: Not yet answered Points possible: 1.00 What statements are always true about limiting reactants? Select one or more: There will be an excess of other reactants at the end of the reaction, The limiting reactant is completely used up in the reaction....
Question 3 Status: Not yet answered Points possible: 1.00 The rearrangement of pinacol occurs in the cation intermediate after losing water as a leaving group. The cation is originally located on the carbon Choose... However, the cation is more stable on the carbon Choose... Therefore, the rearrangement is Choose... from one carbon to another to create Choose... Question 3 Status: Not yet answered I Points possible: 1.00 The rearrangement of pinacol occurs in the cation intermediate after losing water as...
Help me get the correct answers for the pictures and the
question at the bottom.
Cell membranes are semipermeable, and osmosis is an ongoing process in the body. Differences in osmotic pressure inside and outside a red blood cell can result in crenation (shriveling) or hemolysis (rupture). The diagram shows three solutions: an isotonic solution, a hypertonic solution, and a hypotonic solution. Place the appropriate red blood cell in each solution. isotonic solution hypertonic solution hypotonic solution Answer Bank The...
Question 1 Status: Not yet answered I Points possible: 1.00 Consider the reaction corresponding to a voltaic cell and its standard cell potential. Zn(s) + Cu²+ (aq) + Cu(s) + Zn2+ (aq) EO 'cell 1.1032 V What is the cell potential for a cell with a 2.823 M solution of Zn²+ (aq) and 0.1032 M solution of Cu2+ (aq) at 427.9 K?
Question 8 Status: Not yet answered Points possible: 1.00 During a recrystallization, the goal is to form purified crystals of a solid out of solution. However, you might form an oil instead. How should you respond if an oil forms during your recrystallization? Select one: O Filter the mixture to remove the oil and continue with the recrystallization. O Use a separatory funnel and additional solvent to isolate the oil product. O Add more of the recrystallization solvent to form...
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