Question

References Use the References to access important values if needed for this question. For the following reaction, 9.97 grams of sulfur are allowed to react with 21.1 grams of carbon monoxide. sulfur () + carbon monoxide (g) sulfur dioxide (g) + carbon (8) What is the maximum amount of sulfur dioxide that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams Submit Answer ing Reagent: Smaller Amount Method: This is group attempt 1 of 5 Autosaved at 2:01 PM MacBook Air

Answer 1

S (S) + 200 (9) --- Son (9) + 2C (3) No. of moles of Sulfur - mass of sulpur 999 OF SULFUR = 8.979 y = 0.31 moe - 32.06 gmoet No. of molis of co= 21019 - Or to moe 30gnole ACCORDING TO BALANCED Epn. 2 moles CO NEEDS 1 mol so so 01 to moe co NEEDS = - Ootomoe x 1 = 0.35 mes BUT Only 0:31 mor s IS PRESENT so sulfur (S) is LIMITING REAGENT. 1 moe Sulfur Products 1 mol so 0.31 mor sulfur PRODUCES = 0.31 mol x I R = 0.31 mol s02 mass of SO, PROOU WO - 0.31 mol x 6400589 = 1 1909g

No. of moles of Excess co - 0.90- (0131*?) = 0.08 me mass op Exuss co= 0.08 met x 30g no = 12.909