Question

Select the size of a solid steel shaft to drive the two sprockets shown. These sprockets drive 1.75 in pitch roller chains as shown, pitch diameters are 10.632 in and 7.313 in, obtained from the manufacturer's catalog. A 20 hp speed-reducer unit is coupled directly to the shaft and drives it at 63 rpm. At each sprocket 10 hp is taken off. Assume the maximum shear theory of failure, and let .

Tallow = 6000psi

Answer 1

This answer is to find out the size of a solid steel shaft to drive the two sprockets.
Glen data'-- bitch =13141n ; bitch dia =10.632 in and 7.313 in RPM = 20hp PCD3 ->10.632in2 All B 1 c Ų D PcOc - 7.318 in Sy hu ñ Pocerat spocket broup k ' * 5 * 50 % hp - loop and opm = 63 I lohp=fiter I Torque Transmitted by shart 7457W = Torquex 63 x 27/60 Torques 1130.3 N-m shane galben E ... Net Torsional moment on shaft - (ME) 10003.99 lbion * Finding Bending Momentumsi- I upvertical direction (P.); Aprizautal direction (12) 1 * Finding Bearing reactions FBO As

Torque 31000 3.99 = 10,631/2 x P. → 1881.86 Lb o. Ant Rob = 1551,86 Mouncut about A 70 1881.86(5) - R.(15) Horizantal plane ...1000399-7-313 XP T + P3 -1485.qubb A B C D Patro=2735.94 Ik 5 x 5 y 5 & Ra=911-98 lb Resultaut Reactions; R'A=√1254:58 1911.982 R'D=7/1823.967627.282 = 1551.0215 lb =1928.81 lb. point B: (Mb) B=1928.81x10 lb in (Mb) B=19288.185 ebin resultant bending I moment! From Bessastant Maximum shear stress theory diameter 'd' is given as; d = 19/1xT allows V (Mb) + (Mt)? Td =2.64 in