Question

Calculate the [H+] and pH of a 3.11×10^−4M acetic acid solution. The Ka of acetic acid is 1.76 × 10 ^−5.

Answer 1

Guisen. Conen of acetii acid fchz.coot) - 3.11 X10-9M kaf acetic acid. = 1.76X10:5 Solution. - We know that Hot . 80 we can - CHz Cook Chycoot This equation is at equilibrium say that , [CH3 coo-] = [ht ka= [CH3coo] [ut] - [ Chiz cool] - 1.76x10-5 = [ht] [ut] 3:11 x 10-4 54.7 x 10-10 = [ht? Th+] = 154.7 xlorlu - 7:37 X10-5 [nt] = 7.37810.05 M/ Concm of het We knows that - ри = — J• Сн)

Pी - - ०१ [1.33 10-5) - -1097.32 + (-1०५४10-5) - -607 +5 . - ५.13 to.0 - t-tv Jpn = 4:13