Construct a Pushdown automaton that accepts the strings on alphabet {a,b,(, ) }, where parenthesis “(””)” matched in pairs. For example strings “((ab))”,”(a)b()” are in the language, while “((”,”(ab))” are not. Please determine if your PDA deterministic or nondeterministic. (With Proper Steps and explanation) PLEASE DO NOT COPY PASTE THE ANSWER FROM OTHER SOLUTIONS, AND PROVIDE PROPER EXPLANATION AND STEPS.
4. Construct a pushdown automaton for each of the following langauges – by giving its 6-tuple formal defintion and brief/precise interpretations of its states and transitions: (a) {a" x | n > 0, and x € {a,b}* and (x) <n}. (b) {W € {a,b}* | w has twice as many a's as b’s}. (c) (0+1)* — {ww | W € {0, 1}*}
Use a general algorithm to construct a (non-deterministic) pushdown automaton that corresponds to the following context-free grammar with the starting variable S: S → Aab, A → Sba; S → ε. Show, step by step, how the word baab will be accepted by this automaton. Its derivation in the given grammar is straightforward: S → Aab → Sbaab → baab.
Construct a pushdown automaton to accept the following language L = { axbycz where x,y,z >= 0 }
Here are the transitions of a deterministic pushdown automaton. The start state is 90, and f is the accepting state. b E State-Symbol 90-Zo (91AAZO) (92,BZO) (8,8) 91-A (91,AAA) (91) 91-20 (90-20) 42-B (93.5) (92,BB) 92-20 (90,20) 93-B (926) 93-20 (91,AZO) Identify below the one input string that the PDA accepts. babba bababb abba babb
Please Help with this questions with short explanation thank you :) Consider the pushdown automaton with the following transition rules: 1.8(0,0,20) = {(q,XZ0)} 2. 8(9,0,X) = {(q,XX)} 3. 8(q,1,X) = {(q,x)} 4. 8(q,£,X) = {(p,ɛ)} 5. 8(p,£,X) = {(p,ɛ)} 6.8(p,1,X) = {(p,XX)} 7. 8(p,1,20) = {(p,ɛ)} From the ID (p,1101,XXZ0), which of the following ID's can NOT be reached? (p,101,XZO) (p,101,XXXZO) (2,01,XXXXXZO) O (p,01,8) Here are the transitions of a deterministic pushdown automaton. The start state is qo, and f...
Describe (or draw) a pushdown automaton (PDA) that accepts the language L5 in the previous question. Especially if you are drawing the PDA, you must explain your design in 1-2 sentences.
A B-bounded PDA (pushdown automaton) is a PDA M such that it crashes whenever its stack height reaches B. Show that the language {0n1n : n ≥ 1} can not be accepted by a B-bounded PDA for any B.
Consider the following pushdown automaton A: 1, push x O, pop x 1, € / $ E, £ / € . E,$/E start 01 92 Which of the following words are accepted by A? (Select all and only correct answers. Incorrect ones incur a penalty.) 1 11000 11100 € 1100 110