Question

can someone explain why the 10kohm resisitor is canceled out to zero in this problem

15 kr Ex: come from 8 306 3 0 5k verven Node a: Val-30 + 3,10% + Vobo o=0 Vab-Kn-IV = -3.75 U 5x10 15* 16 km Гоол &ike b Ryn = 15 kr 115kr = 16 18 K2 = 3,75 kr 27 km ImA 3.75 kr Thevenin Norton

Answer 1

- Explaination: 15 kn Step!! Here duwring, finding the Thevenin's lomalokrov (3mA Tom o r equivalento accona-b terminal D All the sources are removed, means, circuit-1" a rent sources = open ciuileo woltage socvece = short circuited So, now cirwil- for Theverine equivalent Resistance:- ISK2 Elok2 I shost & 5k2 open Open Comit-2" Step-2: foo explainalios assume test bollege of 1v at the terminals of a-b to find the Theronin equiralent Resistance, o I ISK2 Ise Now, solving circuit Sin open se Jlv I t Iz 14 1 7 loker 5kn I Giv sunt only be Step-3! Her current | Ix = 0 Because, for parallel circuit haven Resi's lomu OA and non-Resistence, c'rrent Moly pay through the non-Resistance TOAL branch. Hone Tu= ol, land I2 = I3/ TOA This is the because of higher cusent in for example lower Resistence part Slelo-U! Hend, by example and explainahin the circull Reduced as: because no current in loks Resistonce, it noa is assumed as open cirlited. Hener Run = 5x 15 = $x 15 = 3.75142 5 +15364 - ob nce it is lon & 5102 F Rth other part del same' whese Oith = -3-75v Isc = -lona