2. (15 points) Two people are pulling a 40-kg box in the opposite directions along the...

Question

Question

Answer 1

Answer #1

a.)

net force = Fnet = F1 + F2

here, F1 = 50 N in +x axis = +50 N

F2 = 30 N in -x axis = -30 N

So, Fnet = +50 + (-30)

Fnet = +20 N

Magnitude = |Fnet| = 20 N

direction = +x axis Or towards right.

b.)

from newton's law,

Fnet = m*a

here, m = mass of box = 40 kg

a = acceleration of box = Fnet/m

a = +20/40

a = +0.5 m/sec^2

Magnitude = |a| = 0.5 m/sec.^2

direction = +x axis Or towards right.

Please upvote.

Answer 2

Similar Homework Help Questions

The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F1...

The helicopter view in the figure below shows two people pulling on a stubborn mule. (Take F1 = 111 N and F2 = 87.0 N.) An illustration shows the helicopter view of a mule being pulled along a forked road in two directions by two men. An x y coordinate system is overlaid on the image, with the origin at the mule's nose, and the mule facing in the positive y-direction. The man on the right is pulling the mule toward...
Two forces of magnitude 30 newtons (N) and 40 N act on an object at angles of 30° and -45° with the positive x-axis as shown in the figure

Two forces of magnitude 30 newtons (N) and 40 N act on an object at angles of 30° and -45° with the positive x-axis as shown in the figure. Find the direction and magnitude of the resultant force, that is, find F1 + F2.
The helicopter view of the figure below shows two people pulling on a stubborn mule. Find:

The helicopter view of the figure below shows two people pulling on a stubborn mule. Find: a) the single force that is equivalent to the two forces shown. (|F1| = 80.0 N and |F2|= 120 N) [R = (39.3 N,181 N)] b) the force a third person would have to exert on the mule to make the net force equal to zero. The forces are measured in units of Newtons (N).

Two forces, F1 and F2, act on the m = 7.29 kg block shown in the...

Two forces, F1 and F2, act on the m = 7.29 kg block shown in the figure above. The magnitudes of the forces are F1 = 62.0 N and F2 = 36.4 N. theta = 68.6 deg. What is the magnitude of the horizontal acceleration of the block?
There are two forces on the 1.86 kg box in the overhead view of the figure...

There are two forces on the 1.86 kg box in the overhead view of the figure but only one is shown. For F1 = 29.7 N, a = 10.1 m/s2, and θ = 30.3°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.) There are two forces on the 1.86 kg box in the overhead view of the figure but...
A 10 kg object on a frictionless table is subjected to two horizontal forces, F1 and...

A 10 kg object on a frictionless table is subjected to two horizontal forces, F1 and F2, with magnitudes F1 = 22 N and F2 = 38 N, as shown in Figure 4-28. 10kg 30 Figure 4-28 (a) Find the acceleration a of the object (0.3 (b) A third force F3 is applied so that the object is in static equilibrium. Find F3 x i)m/s2 i1.64545 X (-41 x i) N |-32.909 A 10 kg object on a frictionless table...

Two forces are acting on a box with mass 6.20 kg to pull it along a...

Two forces are acting on a box with mass 6.20 kg to pull it along a table (picture below). You are looking at the box from above as it is pulled along the surface of a frictionless table. Given the forces below calculate the net acceleration that the box will experience. Give your answer in m/s2. Round your answer to two decimal places. F1 = 29.57 N V1 = 20.64 Degrees F2 = 44.04 N V2 = 48.31 Degrees F2...
1) Two forces F1 and F2 acting on a 40 kg crate have values 150 N...

1) Two forces F1 and F2 acting on a 40 kg crate have values 150 N and 210 N respectively. The angle between them is 50 degree, with F1 acting in the horizontal direction, as shown in the diagram below. Calculate a) the horizontal component acceleration of the block b) the vertical component acceleration of the block c) the magnitude and direction of the total acceleration
11) Bob is moving a 15 kg box along a horizontal floor, by pushing down on...

11) Bob is moving a 15 kg box along a horizontal floor, by pushing down on the box at an angle = 30° below the horizontal with a force of F = 80 N and there is a frictional force of 50 N acting on the box as he pushes. What is the horizontal acceleration of the box? box 12) Using the same information in the above problem, Bob is moving a 15 kg box along a horizontal floor, by...