Question

Constants Acharge of -2.15 nC is placed at the origin of an xy-coordinate system, and a charge of 2.05 nC is placed on the yaxis at y = 3.80 cm Part A If a third charge. af 6.00 nC is now placed at the point z. - 3.15 cm , y -3.90 cm find the x and y components of the total force exerted on this charge by the ather two charges. Express answers numerically separated by a comma VAX th ? FrP,- 1.1.10-4.2.21 . 10-4 N Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B Find the magnitude of this force EVO ALO . N Submit Request Answer Part Find the direction of the force 2 below the + axis Submit Request Answer

Answer 1

Partit distance between I and Iz is V 32=3.15x10m 182 32 7 I 3.80cm X Distance between 19 I and 2 is 3.150m (J3-87 +3759-)x30m 731= 4.93584x102m 3.158152 coso loso= 3.15 4093584-4702 4.93584 Sino- 4.93584 3.8 fi K 14, 11931 32 where, 19,=-3-158109 and 23=58109 9x10x 3.15x109x 57169 (4.9358452x104 For = 5.81836x10-5N wy) = N 31 =-f3, coso fo, sino

>=f-5.81836x105x3.151 4.93584 -5.81836x205 Х 3.8 4.93584 K192115) 532 = no 2 32 N - ĝIN Bi=(-3.7132x1059 -4.4794x105 Pyn where, h=2058109 :: 632= 9x10 x 2.05x109x54109 (3.15)2 x 104 > 2= 9.297x10 SN = Faz? > F2 = 19.297 X10S ... Net force is P = P + F2 F=63.7132 +9.297)x165_4.4794x160 58 =(5.5938x10-59.– 4.4194x1099) allace > Fa= 5.583881050 = N Fy -5 5.-4.4794x10

Part B. magnitude of net force is f= 62 + fy} >f=(165,583894+6-4.479492)x105n If=7.1585X10S N Parta 4. 4794x10 >X O=tan Do 5.5838x10-5 act O = 38.740 below tx asees.