A charge of -4.3 × 10-9 C is at the origin and a charge of 8.1 × 10-9 C is on the x-axis at x = 3 m. At what two locations on the x-axis (xpositive, xnegative) is the potential zero?
A charge of -3.2 × 10-9 C is at the origin and a charge of 8 × 10-9 C is on the x-axis at x = 3 m. At what two locations on the x-axis (xpositive, xnegative) is the potential zero? xpositive = m * 0.85 OK xnegative = m I need the answer to Xnegative with work please Q1
Charges in 1D Q2 A charge of -1.9 x 10*9 is at the origin and a charge of 6.1 x 10 C is on the x-axis at x - 3 m. At what two locations on the x-axis (Xpositive. Xnegative) is the potential zero? m Reset Enter Xpositive 0 NO m Help Reset Enter negative0 0 NO
Q1 Q2 A charge of-3.5 x 10-9 C is at the origin and a charge of 6.9 × 10-9 C is on the x-axis at x = 3 m. At what location on the x- axis is the electric ficld zero?
Charges in 1D Qi Q2 A charge of-1.9 く 10-9 C is at the origin and a charge of 6.1x 10-9 C is on the x-axis at X-3 m. At what location on the x-axis is the electric field zero? x=0 0 NO Holp Reset Enter
A charge of +3q sits at the origin. A charge of -5q sits on the x-axis at the 1.00 m mark. Given that q=4.11 x 10^-9 C, at what location on the x-axis is the electric potential zero? A)0.375 m B)0.500 m C)0.625 m D)0.125 m
12. A particle with a charge of 5.5 x 10-8C is fixed at the origin. A particle with a charge of -2.3 x 10 8C is moved from x = 3.5 cm on the x axis to y = 4.3 cm on the y axis. The change in potential energy of the two-particle system is: a) 3.1 x 10-3J b) -3.1 x 10-3 J c) 6.0 x 10 SJ d) -6.0 x 10-5T e) OJ
A positive charge q1=2*10^-9 C is held fixed at the origin. A small particle with mass m=.004 kg and a negative charge q2=-5*10^-9 C is placed on the x-axis at point A, which is at x=.5m. The particle is released from rest and moves along the x-axis towards the origin. What is the speed of the particle when it reaches point B, which is at x=.3 m? Answer is .00775 m/s Please show work on how to get here
Part A In the figure, charge q1 3x10 C is placed at the origin and charge q2 -84x 10 -8.3 μC be placed such that the resultant force on this third charge is zero? C is placed on the x-axis, at x--0.20 m. Where along the positive x-axis can a third charge O -0.20 m-→ 12 9, Express your answer using two significant figures. X- 10.44 rn
Positive point charge q_1 = +6.0 times 10^-9 C is at the origin and negative point charge q_2 = -4.0 times 10^-9 C is on the negative x-axis at x = -0.200 m. Point A is on the +x-axis at x = 0.100 m and point B is on the +x-axis at x = 0.300 m. How mu Ch work does the resultant electric field of q_1 and q_2 do on a third point charge q_3 = -5.0 times 10^-3...
A charge +7g, where q- 4.11 x 10 C is placed at the origin, and a second charge equal to -3q is placed on the x-axis at the location x=400m Part BFind the location between z = 0and z " 4 00 m where the electric portal passes tract, zeroPart C Find the location in the region r > 4.00 m where the electric potential passes through zero.