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Determine whether the system is consistent 1) x1 + x2 + x3 = 7 X1 -...
The augmented matrix is given for a system of equations. If the system is consistent, find the general solution. Otherwise state that there is no solution. [1 2 -3 51 701 4.5 0000] A) x1 = 15+ 11x3 x2 = -5- 4x3 x3 is free C) x1 = 5 - 2x2 + 3x3 x2 = -5- 4x3 X3 is free B) x1 = 5 - 2x2 + 3x3 x2 is free x3 is free D) x1 = 15+ 11x3 x2...
The augmented matrix is given for a system of equations. If the system is consistent, find the general solution. Otherwise state that there is no solution 5 1 2-3 0 1 4-5 0 0 0 0 X13 15 + 11х3 X2 -5-4x3 X3 = 0 X1 5-2x2 + 3x3 X2 -5- 4x3 = X3 is free X13 5- 2х2 + 3x3 X2 is free X3 is free X13 15 + 11хз X2 = -5-4X3 x3 is free
The augmented matrix is given for a system of equations. If the system is consistent find the general solution. Otherwise state that there is no solution. 1062 01- 29 0 0 0 0 X12 - 6x3 02-9 + 2x3 *3 is free X1 - 2 - 6x3 x2 is free *3- ŹŹ x2 No solution *1 = 2 - 6x3 0x292x3 X30
Consider the linear system x1 + x2 – 2x3 + 3x4 = 0 2x1 + x2 - 6x3 + 4x4 -1 3x1 + 2x2 + px3 + 7x4 -1 X1 – X2 – 6x3 24 = t. Find the conditions (on t and p) that the system is consistent, and inconsistent. If the system is consistent, find all the possible solutions (including stating the dimension of the solution space(s) and describe the solution space(s) in parametric form).
1 Find the value of h for which the following linear system is consistent and find the general solution in vector form of the resulting consistent linear system. x1+ x2+x3 +2x4 = 3 2x1+2x2+3x3+3x4 = h 5x1+5x2+6x3+9x4 = 10 numbers next to x’s are base numbers
The matrix is the reduced echelon matrix for a system with variables x1, x2, x3, and x4. Find the solution set of the system. (If the system has infinitely many solutions, express your answer in terms of k, where x1 = x1(k), x2 = x2(k), x3 = x3(k),and x4 = k. If the system is inconsistent, enter INCONSISTENT.) 1 0 0 0 | −5 0 1 0 0 | 3 0 0 1 0 | −5 0 0 0 1...
1. (10+10pts.) Consider the homogeneous system x1 + x2 + (3 – 2a)x3 = 0 2x1 + x2 + 7x3 - 24 = 0 -X2 + 2ax3 + 2x4 = 0 x1 + x2 + 4x3 = 0 where a is a real constant. a. Find the value of a for which the dimension of the solution space of the system is 1. b. Find a basis of the solution space of the system for the value of a found...
Find a basis for the subspace of R3R3 consisting of all vectors [x1 x2 x3] such that 8x1+5x2−2x3=08x1+5x2−2x3=0. Hint: Notice that this single equation counts as a system of linear equations; find and describe the solutions.
1. CP1 (20 pts) Consider the system of linear equations X1 + x2 + x3 = 1 X1 - x2 + x3 = 3 - X1 + x2 + x3 = -1 a) (3 pts) Provide the Augmented matrix A for this system. b) (9 pts) Find the Row-Echelon Form (AREF) of the Augmented matrix. c) (2 pts) How many solutions does the system have? d) (6 pts) Based on the steps in part b), express Aref as a product...
2x1 − x2 − 3x3 − 2x4 = 1 x1 − x2 − 4x3 − 2x4 = 5 3x1 − x2 − x3 − 3x4 = −2 x1 + 2x3 − x4 = −4