Q8.
V = 50 mL, P = 1 atm, T = 25°C = 298K
find new volume when T = 50°C = 323 K
so
V1/T1 = V2/T2
substitute
50/298 = V2/323
V2 = 323/298*50 = 51.20 mL
ii
V = 2 L of N2gas T = 298K, P = 1 atm
find moles of gas present
mol from ideal gas law
PV = nRT
n = PV/(RT)
n = (1)(2)/(0.082*298) = 0.08184645 moles of gas
mass = mol*MW
MNW of N2 = 28 g/mol
mass = mol*MW = (0.08184645*28) = 2.2917006 g of N2
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