Homework Answers
a)
we have to assume normality distribution with no bias
b)
(Xbar +- t * sd/sqrt(n))
since n = 2500 >> 30
we can use t = z = 1.96
hence
confidence interval is (299774 +- 1.96* 14/sqrt(2500)
= (299774 +- 0.55)
= (299773.45,299774.55)
c)
residuals are randomly distributed
also it has mean = 0, so no bias is satisfied
also n = 2500 >> 30
hence by CLT, it will be normally distributed
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Q 3
Are employees who work more hours per week less satisfied with
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(a)Construct a 95% confidence interval estimate of the
population mean job satisfaction for employees who works 55 hours
per week. The sample mean total hours worked...
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