Given problem is solving by using R-code as;
x1=c(-1,-1,-1,-1,-1,-1,-1,-1,1,1,1,1,1,1,1,1)
x2=c(-1,-1,-1,-1,1,1,1,1,-1,-1,-1,-1,1,1,1,1)
x3=c(-1,-1,1,1,-1,-1,1,1,-1,-1,1,1,-1,-1,1,1)
x4=c(-1,1,-1,1,-1,1,-1,1,-1,1,-1,1,-1,1,-1,1)
y=c(-13.91,-15.04,-13.26,-16.63,-13.96,-15,3.9,3.71,-13.28,-14.61,-13.70,-15.83,-16.03,-16.48,4.98,3.46)
l=lm(y~x1+x2+x3+x4);l
And the output is as;
> l=lm(y~x1+x2+x3+x4);l
Call:
lm(formula = y ~ x1 + x2 + x3 + x4)
Coefficients:
(Intercept) x1 x2 x3
-10.10500 -0.08125 4.42750 4.68375
x4
-0.69750
Thus we get the linear model as;
Response= (-0.08125)*Factor A + (4.42750)*Factor B +(4.68375)* Factor C - (0.69750)* Factor D - (10.105)
Thus the coefficient B0is -10.105
QUESTION 6 Coefficient Bo O -38.295 O -35.410 O -30.895 ?-27.386 0-17.498 10.105 0-2.871 0 5.918...
QUESTION 9 Coefficient B23 O-11.995 0-7.450 O-6.830 0-3.422 O -0.896 0.594 2.427 O 5.006 6.367 O 9.331
Question 3 Which of these equations is a linear model? O Y = bo + b1 X, where X = In(time) Y = bo+by X, where X = time? O Y = bo + b1 X, where X = time O Y = bo + by In(x) where X = time
0 Calculate thre fallasina aus au mieterer ter o) Bo Ce
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