Compute the surface area of revolution about the x-axis over the interval [0,1] for y=e^(−3x.)
(Use symbolic notation and fractions where needed.)
Compute the surface area of revolution about the x-axis over the interval [0,1] for y=e^(−3x.) (Use...
Compute the surface area of revolution about the x-axis over the interval [0, 1] for y = -6 (Use symbolic notation and fractions where needed.) S =
Compute the surface area of revolution of ?=4?+3 about the x-axis over the interval [2,3]. ? = ??
Let F be the equation y=e^5x, let G be the equation x= 7, and let H be the equation y=1 . Find the area of the region enclosed by the graph of these equations.(Use symbolic notation and fractions where needed.) area= (b), Let F be the equation y= sin(11 x), and let G be the equation y= cos(11 x). Find the area of the region enclosed by the graphs of these equations if 0 less than equal to x less...
Compute the integral of the vector field F(x, y, z) = (2x, 29, 42) over (1) = (cos(i), sin(i),1) for OSISK (Use symbolic notation and fractions where needed.) F. dr =
Determine the total surface area and total volume generated by a
complete revolution about the Y-axis of the given figure
Find the area of the surface generated by revolving the curve y= 0sxs6, about the x-axis The area of the surface is (Type an exact answer, using t as needed.) n Enter your answer in the answer box
Find the area of the surface generated by revolving the curve y= 0sxs6, about the x-axis The area of the surface is (Type an exact answer, using t as needed.) n Enter your answer in the answer box
#43 and #47 please
Surface Area - Surfaces of Revolution In Exercises 43–70, a curve C with parametrization = X(t), y=0, z = 2(t), for t in (a, b), is revolved about the z-axis to create a surface S. Find the surface area A of S. NOTE: Only the first four prob- lems are like Example 13.2.7 (a) and you will have to use integrals over two subintervals of [a, b] to compute A. 13. X = t3 – įt,...
3. Find the area of the surface of revolution obtained by rotating the graph of y = 2x around the x-axis for the interval 0 Sxs To Give exact answer only.
Find the surface area of the solid of revolution obtained by
rotating the curve
x=(1/12)(y^2+8)^(3/2)
from ?=2 to ?=5 about the x-axis:
(1 point) Find the surface area of the solid of revolution obtained by rotating the curve X= +8)3/2 from y = 2 to y = 5 about the x-axis:
Find the length s of the path (2 + 141, 3 +212) over the interval 7 <1 38. (Express numbers in exact form. Use symbolic notation and fractions where needed.) s= Find the length s of the path (r + 5,12 + 8) over the interval 5 <1 37. (Use symbolic notation and fractions where needed.) S =