In circuit 1, four resistors are connected purely in parallel to a battery. Three resistors are...

Question

Question

Answer 1

Answer #1

for circuit 1 :

P₁ = V²/R₁ + V²/R₂ + V²/R₃ + V²/6

for circuit 2

P₂ = V²/R₁ + V²/R₂ + V²/R₃ = V² (1/R₁ + 1/R₂ + 1/R₃) = V² /R_p =

given that :

P₁ = 5.1 + P₂

V²/R₁ + V²/R₂ + V²/R₃ + V²/6 = 5.1 + V²/R₁ + V²/R₂ + V²/R₃

V²/6 = 5.1

V = sqrt(6 x 5.1) = 5.53 volts

Answer 2

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