Question

8. -/2 points ASWSBE13 3.E.016.MI. My Notes The grade point average for college students is based on a weighted mean computation. For most colleges, the grades are given the following data value A (4), (3), (0). Alter 60 credit hours of course work, a student at State University and credit hours of A, 10 credit hours of B, 2 credit hours of C, and 4 credit hours of D. (a) Compute the student's grade point average Ask Your Teacher (2), D (1), and first credit hours of course work in order to be t ted to the business college. We this student be (b) Students at State University must maintain a 2.5 grade point average for the admitted Need Help?

Answer 1

i Question 8 we have 60 =1 credit hours of cource work . a student at state university ecroned g credit hours A, 19 redit hours of B, - 28 credit hours c,& a credit hours of O. » students grade point average: = CA +8tc to) grades = [60] cols 04. 6 students at state university must maintain a - 2.5 grade point average for their first so redit hours of course work in order to be admitted to the business college will this student be admitted * No. because here already A B, C, D grade

consider if we consider as then we should consides other gradesike E.or F question 10 we have data (sompie) la average =$3.28 here nazo observations given. tet R= [3.39 3.79.4.79.9.56, 3.75, 3.9), 3.85,3.80, 3.55, 3.76 3.77, 389, 3.75, 3.49, 4.15,3.46,3-83, 3.43, 3.41, 3.37] ☺ estimate meon - 7=ER = (3.39 + 3.79 f - -.-t 3.41 +3.347 20 - 15? [= $346

1 e sample standard deviation asr where s = 4 Elti-zes? :52 = I (19.79 -3.76)2+(3.89-3.7632+ -. - --+(3.41- 3.7612+(3:37-3.7619 - 11.8950) 20.099768 | Sx = so.099768 = 0.315861) 14 © compare here the average price sample for a mean gallon is higher than of unleashed gasoline

of unleash than the the cost of it would be price chose =) The average price for a gallon Sassline in ran Fransisco is higher national average. the indicates that living in San Fransisco is higher for cities that have an average to the national average. 90 consider a sample mean = soo standard deviation = 100 z score for sso = (sso - 500) 100

2 score for 660 = 560-500 E 16 DD 2 score for goo= o z score for 4+0 = 470 500 6 -03 z score for 270 = 270 -500T = -2-31 Score fer -03 100 100 son 12 , we have M=6.9, o= 1.4 6 use cheby sher's theorem to calcware the minimum percentage of individuals who sleep between 4. 14 9.7 hours. & chebyshers thm = the proportion of values from a data set that will fall within k standard deviation

of the mean will be at least int where k is number greater than a - o substract the large value - mean e q.-69] = 2.8 @ta difference = 20 16 021 1 i = - = 116045 95 = 751 o use cheby shers thim to conclude the minimum percentage of individuals who steep between 3:44 10.6. ។

0 subtract the large value - mean = 10.4 – 619 = 3.5 @te difference - 3.5 E 2-5 ] 1- = icensiz = 1-0.16 50.84 :.847.] o use emperical rule individual sleep between 4.1 € 9.7 emperical rule = 68% - 95%. - 94.7). 681. observation falls within 14 to) [(4-0), CH+6)] = [(69-1-4), (6.441.437

= [ 5.5, 8.3] 95% observations falls within [ H £ 20] = [ 6.9+(21.4)] ? 16.9 + 2.8] = [4.1, 4.73 1 Answer = 953. Now compone © ¢ © the % obtained using the emperical rule in greater than the percentage obtained using cheby shers theorem.