Question

Series and parallel RL and RC circuits with an AC source. A 60 Hz voltage source has an amplitude of V 120 V. For the following problems, compute the indicated phasors including bath magnitudes and phase angles, and sketch the phasor diagrams (no submission)

Answer 1

Summary - it is basic problem so I have shown step by step solution .
"X_c = -J 2.5 c X_c = 2.5 angle -90 degree X_c = -J 2.55 a) Vertical-bar IR Vertical-bar = -V_T/R = 120/7.8 = 15.38 A b) angle I_R = angle V_T/angle R = angle 0 degree/angle 0 degree = angle 0 degree c) Vertical-bar I_c Vertical-bar = 120/ Vertical-bar x_c Vertical-bar = 120/2.5 = 48 A d) angle I_c = angle V_T - angle X_c angle I_c = angle 0 degree - angle -pi/2 = 90 degree I_c = 48 angle 90 degree \r\n e) I_T = I_R + I_C I_T = 15.38 + 48 angle 90 degree I_T = 15.38 + J 48 Vertical-bar I_T Vertical-bar = 50.40 A f) angle I_T = tan^-1 (48/15.38) angle I_T = 72.23 degree g) Z_T = R"" - J X_C Z_T = 7.8 times -J2.5/7.8 - J2.5 Z_T = -J 19.5/7.8 - J 2.5 = 2.38 angle -72.23 \r\n Vertical-bar Z_T Vertical-bar = 2.38 Ohm h) angle Z_T = -72.23 degree"