Ans:
Given that
Uniform distribution with a=380 and b=390
a)mean=(a+b)/2=(380+390)/2=385
variance=(b-a)^2/12=(390-380)^2/12=100/12=8.333
standard deviation=sqrt(8.333)=2.89
b)
F(x)=(x-a)/(b-a)=(x-380)/10
Probability that length is within one standard deviation of the mean=2*2.89/10=0.578
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