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2. (Problem 4.5 from the textbook.) Using the time-distance values given in the table below, interpret the subsurface geology

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Answer #1

Solution

From the figure

As we know that

T2=T02+ X2 /V2

Where T= Two way travel time

T0= Echo time

X= offset distance

V= velocity of layer

Slope of Graph give V2 and intecept on Y- axis give T02

From Graph between T2 vs X2 47000 45000 43000 42000 41000 (12 39000 37000 T2 4000 ms square) 32000 31000 (2*2 28000 (B1A2 21000 18000 17000 16000 5000U 1

In Above Graph VV' line are First Reflector and WW' line are second Reflector

and UU' line are third  Reflector

slobo. = 29000-6000 68oo- 1oo ズ4z uooo V2 0 8528 v2 = \ !12.. 6 h,//s

lo pe700o-15000 2000 4000 TUors echo time 2 Тог 1800 To 3 : 114.ouチ T03: 1-1和 Sc c . u2.y2 ms. 02 6 ะ 1.025 sec

To= echo time Vs Velocity d2 = 600.9 m of3 Tq3·Vz-1-1.to x lui q.2 2- 3 = 92 31 m

725 t-1-1 : u, SS.ol (p)H4盖 0

Data Table

T(1)2T(2) T(2)2 T(3) T(3)A2 40.5 1640.25102.5 10506.25116.8 13642.24 47.72275.29103.1 10629.61117.2 13735.84 118 13924 77.2 5

Please thumb up ....... Thanku

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