E. Use the thermodynamic quantities given below to calculate the theoretical ?H for this
reaction: NH3 + HCl ? NH4Cl
?? ?H
E. Use the thermodynamic quantities given below to calculate the theoretical ?H for this reaction: NH3...
Consider the reaction: NH4Cl(aq)NH3(g) + HCl(aq) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.81 moles of NH4Cl(aq) react at standard conditions.
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ /kJ mol-1 -314.4 -45.9 -92.3 Smº /JK-mol-1 94.6 192.8 186.9 Cp.m /JK-mol-1 84.1 35.1 29.1 Do not use the Van't Hoff equation, In(K/K) = -(AHR/R) (T2-1-T1-1) The value of the thermodynamic equilibrium constant is Kp = Number
Consider the reaction NH4Cl(aq)NH3(g) + HCl(aq) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K. ANSWER:
Consider the reaction, NH3 (8) H HC ENH1G(s) Given the following table of thermodynamic data at 298 K: Substana | AH¢{kj/mol | Sº C/K-mol) NH3 (5) 16:19 192.5 HCl (8) 92150 186,69 NHCl (s) 13144 94.6 The value of K for the reaction at 25°C is
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ 7 kJ mol-1 -314.4 -45.9 -92.3 Smº JK-1 mol-1 94.6 192.8 186.9 Cp,m 84.1 35.1 29.1 /JK-1 mol-1 Do not use the Van't Hoff equation, In(K /K1) = -(AHR/R) (T2-1 - 7,-1) The value of the thermodynamic equilibrium constant is Kp= 7.6e14
Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. HCl(g) + NH3(g)--->NH4Cl(s) K =
Please do I do rate :) Consider the reaction NH4Cl(aq)-NH3(g) + HCl(aq) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K. ANSWER:
Calculate the ΔH0 for the following reaction: NH4Cl(s) → NH3(g) + HCl(g) Given the following standard enthalpies of formation ΔHf0 (298 K, 1 atm) NH3(g) -46.2 kJ mol-1 ; HCl(g) -92.3 kJ mol-1 ; NH4Cl(s) -315.0 kJ mol-1
Consider the reaction: NH3 (g) + HCl (g) → NH4Cl (s) Given the following table of thermodynamic data at 298 K: Substance! AH/M/mol) I s。(J/K-mol) NH3 g) HCI (g) NHCI)-3144 -46.19 -92.30 192.5 186.69 94.6 The value of K for the reaction at 25 °c is
Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K