Question

v = eue for every 6. Let V be the set of positive real numbers. Define the operations u u and v in V, and cou ecu for every

Linear Algebra Subspaces.

Correct answer is E - please help explain why. I do not understand the concept. Thanks!

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Answer #1

Not Inorder ko show that a Veclvispace U is closed under an oper ahon *, we have to chow that fov ujve U huiv e v So, hereoe knou that for ang real number *. e » IS Also, e* is a real number 5o, we have e and e are real numbers we know if a and bSo, ís closed under we will show lit) we have bo ehow v i cloaed under co is trueTor that we have to chow for any re number c and ueV, еОиє1 al toy any real number c, (whether pooiive megative or zer) ec e

We Know, e*u (since M. a a mナn Particoul arlyee- e utV e- e NJow lwill also show that (w) is false iven, cou 0 e is not ha

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