Question

6. Molybdenum is a BCC structured atom with a 3.1408 angstroms and atomic weight equal to 95.94g/mol a. (1 pts) Determine the
4. (1 pts) Common metallic structures are FCC, BCC, and HCP. Coordination number and atomic packing factor are the same for (
0 0
Add a comment Improve this question Transcribed image text
Answer #1

BC Skuture x(Noof.urnoso tomy )ナCeh = 3 3 Co-oselination 8 Atomic.meignt=qmyg/ Tz Yeoltus 여.Un.ㅏ o 023X10* 23 2 31.9282 A) loNづ 12 12 8- 6 FC 。..70 0 Scc Ans c

Add a comment
Know the answer?
Add Answer to:
6. Molybdenum is a BCC structured atom with a 3.1408 angstroms and atomic weight equal to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The atomic weight and atomic radius for a hypothetical BCC metal are 43.1 g/mol and 0.122...

    5 The atomic weight and atomic radius for a hypothetical BCC metal are 43.1 g/mol and 0.122 nm respectively. Determine its density.  6 Calculate the radius of a iridium atom, given that Ir has a FCC crystal structure, a density of 22.4 g/cm^3, and an atomic weight of 192.2 g/mol.

  • Given Values Atomic Radius (nm) = 0.18 FCC Metal = Silver BCC Metal: = Sodium Temperature...

    Given Values Atomic Radius (nm) = 0.18 FCC Metal = Silver BCC Metal: = Sodium Temperature (c) = 1127 Metal A = Zinc Equilibrium Number of Vacancies (m^-3) = 7.42E + 23 Temperature for Metal A = 247 Metal B = Calcium If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm^3 Your Answer = What is the atomic packing factor...

  • 1) Cite the difference between atomic mass and atomic weight. 2) Without consulting any figures or...

    1) Cite the difference between atomic mass and atomic weight. 2) Without consulting any figures or tables, determine whether each of the electron configurations given below is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices. (a) 1s22s22p63523p63d7452 (d) 1s22s22p6352 (b) 1s22s22p63s23p6 (e) 1s22s22p63s23p63d2452 (C) 1s22s22p5 (1) 1s22s22p63523p6451 3) (a) What type(s) of bonding would be expected for each of the following materials; brass (a copper- zinc alloy), rubber, barium...

  • --Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature...

    --Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature ( C ) = 1017 Metal A = Tin Equilibrium Number of Vacancies (m-3) = 6.02E+23 Temperature for Metal A = 369 Metal B = Gallium 1) If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm3? Write your answers in Engineering Notation.          ...

  • (a) Differentiate between Face- Centered Cubic (FCC) and Body-Centered Cubic (BCC) crystal structures. Why FCC metals...

    (a) Differentiate between Face- Centered Cubic (FCC) and Body-Centered Cubic (BCC) crystal structures. Why FCC metals are more ductile than BCC metals? 5 marks) (ii) show the relationship between the unit cell edge length, a, and the atomic radius, R, for a BCC crystal. Iron has a BCC crystal structure, an atomic radius of 0.124 nm, and atomic weight of 55.85 g/mol. Calculate its theoretical density Given: Avogardo's Number is 6.02 x 105 atoms/mol (5 marks) Figure 1 Determine the...

  • Atomic densities and atomic volumes Problem 3. In this problem, we will calculate the atomic density...

    Atomic densities and atomic volumes Problem 3. In this problem, we will calculate the atomic density ) and atomic volume () of two different pure metallic solids, Iron (Fe) and aluminum (AI). We will compare and contrast two different calculation methods flabeled Method I and Method II below. We will exploit the technique of "DIMENSIONAL ANALYSIS in our calculations. Method I. Calculate p and n based on knowledge of the mass density of the solid (the symbol for mass density...

  • 16) An atom with a valence structure of 1s 2el 2nf 3ed 3pf 4e 3d would...

    16) An atom with a valence structure of 1s 2el 2nf 3ed 3pf 4e 3d would behave most like a) Transition metal b) Alkal d Alkaline earth Part C) Multiple Choice (30 points, 3 pts each) d) Inert element e) Actinide n Isotropic 17) What statement below is true when comparing ideal HCP and FCC structures? al Elements with both are very ductile b) Atoms touch along the [100) directions c FCC metals have lower den d) None of the...

  • Units: NA= 6.02×1023 atoms/mol Walter White who lives in Simeranya (a utopic city in Anarres) prepares...

    Units: NA= 6.02×1023 atoms/mol Walter White who lives in Simeranya (a utopic city in Anarres) prepares blue crystals, named as myth, which adopt a side-centered cubic (scc) cell with a molecular formula of A.B Side-centered cubic (scc) cell Top view 1. Determine the molecular formula of myth. 2. Calculate the atomic packing factor (APF) of scc unit cell. The atomic radii of A and B are equal to 120 and 132 pm, respectively. 3. Calculate the density of the myth...

  • 1. Compute the percent ionic character of the interatomic bonds for each of the following compounds:...

    1. Compute the percent ionic character of the interatomic bonds for each of the following compounds: TiO2, ZnTe, Csci, InSb, and MgCl2. Calculate the number of vacancies per cubic meter in iron at 850°C. The energy for vacancy formation is 1.08 eV/atom. The density and atomic weight for Fe are 7.65 g/cm3 and 55.85 g/mol, respectively 3. Molybdenum forms a substitutional solid solution with tungsten. Compute the weight percent of molybdenum that must be added to tungsten to yield an...

  • need some explaining plaz. ke ke 12. Calculate the atomic weight of Kelsium, a fictional element,...

    need some explaining plaz. ke ke 12. Calculate the atomic weight of Kelsium, a fictional element, if it consists of two isotopes with the following abundance and masses: 11.99 amu 66.00% 13.98 amu 34.0096 A. 11:44 amu B. 8.958 amu C. 13.01 amu D 12.67 amu E 25.97 amu 13. Which of the following can we conclude from the atomic weight of boron which is comprised of just boron-10 and boron-11? A Boron-11 is the most abundant isotope. B Boron-10...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT