Question

ME 353: Manufacturing Processes Homework 8 (20 Points) 4.00 0.35 R1.50 1.00 1.00 1.50 2.00 3.00 4.00 6.00 7.00 8.00 The outline of the part in problem 1 is to be profile milled using a 1 inch diameter end mill with four teeth. The part is 0.50 in thick. Cutting speed = 200 ft/min and feed = 0.005 in/tooth. Use the lower left corner of the part as the origin in the x-y axis system. Two of the holes in the part have already been drilled and will be used for clamping the part during profile milling. Write the part program in G-code to create the part. Use absolute positioning. Use down-milling to create the part.

Answer 1

Please find the solution attached

cuter path S 35 .635 #sty HT $25 H2 425 H3 $25 rotation Colore 0 (0,0) A (0,2-5) Thickness 0.5 in. B (105,4) c (6.5,4) D (8,205) E (8, o) Hi (11) H3 (71) H₂ (6,1) Tool start point Hy (3,2) its (2,3) Ho (4,3) Assumption & other points y te aty drechon as shown in Fig. tz is to outward. 2) z =0 is machine table plane.. Melling is done in clockouise drechos. ie o A B C D EO. Therefore cutter diameter compensaton left (G41) is used. 4) Since downs milling is to be med, spindle rotates in clocleouise direchon. (MO3) de 5) The diameter offeet values for the milling tool coll be automatically taken from the database of CNC by the controller. 6) Tol is the tool position for milling tool Todo i i c 25 drill bit. T03 1 1 1 050 doll bit TO4 . " 435 drill bit. 7) tall Drilling canned cycle not used.

0 0 ( Cutting Parameters For programmung we need RPM of spindle & Feedrale cutting speed - 200 Ft/min = 2400 in/min (catting velocity we know cutting velocity TDN in/mun where De Dia of cutter Nz rpm. ITXI X N = 2400 N = 7648pm This rom need not be followed incase of drilling Feed F) = 0.005 in/tooth (4 teeth for cutter) for Nrpm, 480 times teeth comes into contact per minute ii F = 0.005x4x764 in /min = 15.28 is/min For Better understanding Lets begin G cole section. explanation of each line is provided.

modal codes. Once it is Gol, G41 are given no need to give next blue s. for commentng N100 G90 G2o; //Absolute positoning, inch input NILO TO MOG/Executing Toolchange. N120 GOO xo y-a z i ; Rapid positioning tool 1 above starting point N130 Gol xo; //rool move downwards to table. I N140 M03 5764;//spindle starts cw at 764 rpm. F 15.29 NISO GOI G41 A XO yoki offset initialisation of tool mover to 0.5" lef tof origin N160 42.5; Kutten movers to A along path. (with feedrale ) N170 X 1.5 74 : Ilmoves to Bu NISO X6. 5 lmoves to c N190 GOR X8 y 2.5 R15: Circular interpokhan CW with R=1.5 N200 GOI X8 yo ;//moves to E NQIO XO moves to origin N220 z 1 Hool taken up. N230 TOR MO6; // Tool change N240 M03 Mo3 S150 S1500 ; 11 spindlestart cm 1500rpm N250 Goo XI XI 21 11 spindle above HL N2GO GOI 20 F50 Drills hole HL. N270 21; 1 tool retracts. N250 TO3 MOG; Il tool change N290 GOO X3 72.; // tool above te N 300 MO GOI zo F50 s1500 M03; 11 hole cutting a dom N 310 21 Hool retracts N320 TO4 MO6;ll tool change. N330 Goo X2 43; Tool above Hs

N340 GOL 20 F50 S1500 M03; Il doill holeat its N350 21; tod retracts. N360 Goo X4 ;l tool above H6. N370 Gol zo F50 1500 Mo3; // drills hole at H6. N380 21;//tod retracts. N390 GQ8; // returns to home position N400 Mos; // Spindle stop N410 M30; // End of programs. Hole at already ₂ & H₂ is considered as drilled holes as said inqueshon