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#include <iostream>
using namespace std;
int main() {
int n ;
do{
cout<<"Enter an odd integer between 10 and 20: ";
cin>>n;
}while((n>20)&&(n<10));
char a[n][n];
for(int i=0;i<n;i++)
{
for(int j=0;j<n;j++)
{
if((i==0)||(j==0)||(i==(n-1))||(j==(n-1)))a[i][j]='X';
else if(i==j)
{
a[i][j]='X';
}
else if ((i+j)==(n-1))
{
a[i][j]='X';
}
else
{
a[i][j]='-';
}
}
}
for(int i=0;i<n;i++)
{
for(int j=0;j<n;j++)
{
cout<<a[i][j]<<" ";
}
cout<<endl;
}
return 0;
}
![C++14 14 Shortcuts S Reset Copy for(int j=0; j<n; j++) if((i==0)||(j==0)||(i==(n-1))||(j==(n-1)))a[i]: else if(i==j) 15 - a[i](http://img.homeworklib.com/questions/e9903ed0-b8c4-11eb-a09c-6dd49556d995.png?x-oss-process=image/resize,w_560)
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Nested loops
c++ nested loops
1. Request an odd integer value between 10 and 20. Input...
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These are the hints:
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Using Python, Can someone please assist in the following:
These are the hints:
Summary This week's lab is to create a simple multiplication table using nested loops and if statements. Prompt the user for the size of the multiplication table (from 2x2 to 10x10). Use a validation loop to display a warning if the number is less than 2 or greater than 10 and prompt the user to enter the data again until they enter a valid number Put a...
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