Question

wolod covig lolom od nimeona ni upenwolle would 8a) Hydrogen gas (H2) and fluorine (F2) are placed at opposite ends of a 200 meter tube. Where will they meet? H2 = 2.02 g/mol and F2 = 38 g/molo mod gniwollte no nosibirdydd add E lo obam ad olidorasidalsvolto abbonsided lower to color zirl lobo od tat oldizzoq oli tud blog moll solo in zang basa barolo o moltoloo to sito di idon 8b) If you heat just the fluorine, at what temperature will the hydrogen and fluorine meet 80-X meters from the hydrogen side? Assume that the H2 is at 25°C. Baldinho blo

Answer 1

(8a lm * 4200-13m F2 Ha HE F 2007 rate of diffusion ferroulas MF2 Ito MF2 = 38 gon/anal mha = 7.00gmisel Мін, lfa a 38 200-1 2.02 s 118.811 200-l 40337 = 200-1 4.337 (200-1) = 1 86714 - 4.3371 = 1 86704 5.337 867.4 - 5.3371 → l = I = 162.5257 They will meet at 162.5257 m from Hel Answer

Effect of temprature on Rate of differsion - 3 M2 li Ta l THE MF2 Х TF2 mita lha уға TE=? TH2=25+ 278 = 298k ma= 38glonas MH2 = 2.099/mes 3 8 38 298 no 80 = 120 l Ha= Fa= 800 X 2.02 42 TF2 11324 -- mlar .X 2002 et both sides on Suning 11324 oft X TF2 2.02 TF2= 9 11324 x 4 2.02 TF2 = 2491.5k t's of F2 = 2491.5-373 tef = 2218.5°C