Question

The process is here but we need help with the answers. The resistance values are all here and the process, we just need help with the actual answers of the circuit and the total values of resistance, voltage, and current.

RI 50 S2 150.0 2 R4-40.0 R5 250.0 60.0 S2 R7* 350.0 80.0 S2 R9 85.0 S2 R10 375.02 RI 65.0 R12 275.0 S2 R13 225.02 R14 35.0 R15 25.0 S2 R16 5.02 R17 91.5 R18 5.2 S2 R19 3.4 S2 R20 55.4 R21 01.5 S2 98.0 R23 44.0 S2 R24 21.32 R25 23.7 S2 R26 32.0 S2 R27 33.9 R28 39.72 R29 51.1 R30 261.52 54.8 R32 58.9 R33 R34 6.00 S2 R35 9.00 R36 60.0 R37 R38 90.00 R39 21.0 S2 R40 9.0 S2 R4 80.0 R42 3.0 S2 R43 0.02 R44 35.0 20.0 R45

Answer 1

Devide the circuit into three parts 1. Left top, 2. Left bottom.and 3. right top determine the net resistance in the left top, 15.2+134+( (101.5)(554) (101.5+554) +98 144+21.3+23.7+132 33.9+39.7 All above three are in parallel -++x43.74 x 162.438 321 73.6 PLeftep -91.5+43.74-135.24 determine the net resi stance in the left bottom, RLet totcom - 50+17.64+21.89+42.61+27.34+33.57+15 208.06 determine the net resi stance in the right top 51.1+241.5+54.8+58.9 406.3 15+3.39+5.248+4.866+20 48.5 The above both are in parallel (406.3 (48.5) 406+(485) 43.32 Left bottom nad top are in parall el (208.06) (135.24)-1 96 (208.06)+(13524) Finally RiR and right top are in series, R,,-(81.96)-(43.32)-125.28 Ω Th ecurrent throught the left bottom is 2.5 A = 1,R = (2.5)(208.06) = 520. 15 V The left top is parallel to the 520.15 V V 520.15-3.84 A R 135.24 Total current I -3.84+2.5-6.34 A The voltage across the right top partis (6.34) (43.32) 274.64 V The net voltage is V 520.15+274.64794.79 V