Question

The citizens of Paris were terrified during World War I when they were suddenly bombarded with shells fired from a long-range gun known as Big Bertha. The barrel of the gun was 36.6 m long and it had a muzzle speed of 1.400 km/s. When the gun's angle of elevation was set to 53.00 degree, what would be the range? For the purposes of solving this problem, neglect air resistance.

Answer 1

Range R = (Vcos $\Theta$ )T

time of flight T = 2Vsin $\Theta$ /g = 2*1.4*10³*sing53/9.8 =228 seconds

Range R = (Vcos $\Theta$ )T = (1.4*10³ *cos53)*228 = 192252 m

another formula for Range R = V²sin2 $\Theta$ /g = 192252 m