Question

Please help me write a Pseudocode (please do NOT answer in JAVA or Python - I will not be able to use those). Please ALSO create a flowchart using Flowgarithm program. Thank you so much, if answer is provided in Pseudocode and Flowchart, I will provide good feedback and thumbs up to the resonder. Thank you!

Tic-Tac-Toe Game Write a program that allows two players to play a game of tic-tac-toe. Use a two- dimensional char array with three rows and three columns as the game board. Each element of the array should be initialized with an asterisk (*). The program should run a loop that

1. Displays the contents of the board array

2. Allows player 1 to select a location on the board for an X. The program should ask the user to enter the row and column number.

3. Allows player 2 to select a location on the board for an O. The program should ask the user to enter the row and column number.

4. Determines whether a player has won, or a tie has occurred. If a player has won, the program should declare that player the winner and end. If a tie has occurred, the program should say so and end.

5. Player 1 wins when there are three Xs in a row on the game board. The Xs can appear in a row, in a column, or diagonally across the board. A tie occurs when all of the locations on the board are full, but there is no winner.

Note: You may declare the winner if you cannot figure out how to have the computer figure it out.

(response only in Pseudocode and Flowgarithm please - do not respond with JAVA or Python)

Answer 1

PseudoCode for TIC-TAC-TOE Program.

1. Initialize array(A[(0..3)(0..3)]) for matrix board
2. Initialize (rx,cx) and (ro,co) to take input from user
3. Initialize gameEnds = false.
4. while(!gameEnds)
   1. display "Player 1 ! Enter your row and column"
   2. (cx,rx) = take input from player 1
   3. if A[(cx),(rx)] is not NULL
      1. display "Invalid location"! localtion already have A[(cx)(rx)]
      2. Goto Step 4.1
   4. else
      1. A[(cx)(rx)] == 'X'
      2. if board has 3-Xs in a row, column or diagonally
         1. display "Player 1 wins."
         2. gameEnds = true
         3. break
   5. display "Player 2 ! Enter your row and column"
   6. (co,ro) = take input from player 2
   7. if A[(co),(ro)] is not NULL
      1. display "Invalid location"! localtion already have A[(co)(ro)]
      2. Goto Step 4.5
   8. else
      1. A[(co)(ro)] == '0'
      2. if board has 3-0s in a row, column or diagonally
         1. display "Player 2 wins."
         2. gameEnds = true
         3. break

Code to check winning situation

1. consider input as Array(A[(0...3)(0...3)] and MatchOperator('X' or 'O'))

Diagonal Condition

1. if matchOperator exists as [(0,0) and (1,1) and (2,2)] return True

Horizontal condition

1. if matchOperator exists at [(0,0) and (0,1) and (0,2)] or [(1,0) and (1,1) and (1,2)] or [(2,0) and (2,1) and (2,2)] return True

Vertical condition

1. if matchOperator exists at [(0,0) and (1,0) and (2,0)] or [(0,1) and (1,1) and (2,1)] or [(0,2) and (1,2) and (2,2)] return True

else

return False.