An air filled cylinder has 2800 turns and it is 2.5 cm in diameter and 28.2 cm long
a)
indutance = eo N^2 A /L
i = 4 x 3.14 x 10^-7 x 3200^2 x 3.14 x .0125 ^2 / .299
i = 21.11 mH
b)
21.11 = k 3200^2
21.11= 1200 k N^2
N = 1.63 = 2 turns
What is its inductance? b) How many turns would you need to generate the same inductance if the core were iron filled insted ? assume the magnetic permeability of iron is about 1200 times of that free space
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