Are
A concentration cell was made using a silver metal electrode in a saturated solution of Agl...
Using Ksp to Calculate Eindicator Calculate the potential of a silver electrode immersed in a solution that is saturated with Agl and has an activity of exactly 1.00. Ksp(Agl) = 8.3x10-17 and E°[Agt/Ag(s)] = + 0.799 V.
A silver electrode is placed in a saturated solution of AgBr. This half-cell is connected to a standard hydrogen electrode and the voltage is found to be +0.437 V. calculate Ksp for AgBr.
44.) A voltaic cell is constructed from the following items: Silver metal electrode Calcium metal electrode 1.0 M Silver nitrate solution 1.0 M Calcium Nitrate solution Salt Bridge 45.) For the voltaic cell described above, which material is the anode? Question 44 3 pts A Voltaic cell is constructed from the following items: Silver metal electrode Calcium metal electrode 1.0 M Silver nitrate solution 1.0 M Calcium nitrate solution Salt bridge What is the standard cell potential for the Voltaic...
One electrode of a spontaneous electrochemical cell contains a piece of lead metal dipped into saturated solution of PBSO4 in 1.00 M SO4. The other electrode is a standard hydrogen gas electrode. a) Draw and label all aspects of the electrochemical cell. b) Write the half reactions and the overall electrochemical reaction. c) Determine the emf (Ecell ) for the cell. 1.7 x 10% Ksp PbSO4 Pb (aq) 2 e Note: 2+ E -0.13 V Pb (s)
In a copper-zinc voltaic cell, one half-cell consists of a ZnZn electrode inserted in a solution of zinc sulfate and the other half-cell consists of a CuCu electrode inserted in a copper sulfate solution. These two half-cells are separated by a salt bridge. At the zinc electrode (anode), ZnZn metal undergoes oxidation by losing two electrons and enters the solution as Zn2+Zn2+ ions. The oxidation half-cell reaction that takes place at the anode is Zn(s)→Zn2+(aq)+2e−Zn(s)→Zn2+(aq)+2e− The CuCu ions undergo reduction...
One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining
1. Write the half‑reaction for the silver-silver chloride reference electrode. Include physical states. 2. Write the half‑reaction for the saturated calomel reference electrode. Include physical states. 3. What is the potential of the cell: silver–silver chloride electrode || saturated calomel electrode given that the potential for the Ag∣∣AgCl electrode in a saturated KCl solution is +0.197 V and the potential for a saturated calomel electrode is +0.241 V?
Write the half-reaction for the silver-silver chloride reference electrode. Include physical states. half-reaction: Write the half-reaction for the saturated calomel reference electrode. Include physical states. half-reaction: What is the potential of the cell silver-silver chloride electrode || saturated calomel electrode given that the potential for the Ag AgCl electrode in a saturated KCl solution is +0.197 V and the potential for a saturated calomel electrode is +0.241 V? E=
a.) A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is a hydrogen electrode (P(H2) = 1 atm) immersed in a solution of unknown [H+]. If the cell potential is 0.204 V, what is the pH of the unknown solution at 298 K? b.) An electrochemical cell is constructed in which a Cr3+(1.00 M)|Cr(s) half-cell is connected to an H3O+(aq)|H2(1 atm) half-cell with unknown H3O+ concentration. The measured cell voltage is 0.366...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...