Let, speed of ball be V m/s.
then, ball travels a distance of 24 m in horizontal direction in 2.2 seconds.
therefore, horizontal velocity multipied by time taken = horizontal distance covered.
=>
b) in vertical direction, acceleration is g = 9.8 m/s^2. in 2.2 seconds vertical displacement be S.
then
distance by which it clears the wall= 8.13- 6.90 = 1.23 m
c) Total time after which it lands on playground be t seconds then,
taking the higher value as it has hit the playground while falling,
therefore required distance = meters.
Please help solve! 12. A playground is on the flat roof of a city school, hb...
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