Sol:
1:
Since each bag is independent from other so probability of getting blue ball time is
P(B) = 0.24, P(N) = 1 -0.24 = 0.76
Each ball can be blue or not blue so according to fundamental principe of counting total number of outcomes is
2 *2*2*2 = 16
Following is the tree diagram of the four draws (one from each bag):
Here outcome NNNB shows the balls from first three bags are not blue and ball from last bag is blue.
2)
Yes it is binomial experiment. Let X is a radnom variable shows the number of blue balls out of 4. Here X has binomial distribution with parameters n=4 and p=0.24.
The pdf of X is
3)
The probabilites are:
Following table shows the required probability;
X | P(X=x) |
0 | 0.3336 |
1 | 0.4214 |
2 | 0.1996 |
3 | 0.042 |
4 | 0.0033 |
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4:
The mean is
The standard deviation is
5:
(a)
The probabiluty that at least three candies will be blue in this experiment is
(b)
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