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Problem 2 (3.104) Use both nodal and loop analyses to find lo. 1 kN} 1 kn B 2V, Žika 2 ma 2: 12v 1knižv
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Given circuit -2Vx+12 Lool2 71 Т!ь. lk Io 1 kw МУ, XX ...:-) ТЕ ...,.> NA 5 san Soy mv 2017 w Apply Loop analysis: -12 + (1 kModal method: Apply nodal analysis at Na -(-2 Uxt12 12- VX 1kW = Vx x + 2 Ux-12 12-vx + 5Ux =24 x = 20 1км so, from nodal vol

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