(a) X- coordinate of center of mass = (m1*x1 + m2*x2 + m3*x3) / (m1 + m2 + m3)
= (2.3*0 + 4.0*2.0 + 9.0*1.0) / (2.3+4.0+9.0)
= (0 + 8.0 + 9.0) / 15.3
= 1.11 m
Y- coordinate of center of mass = (m1*y1 + m2*y2 + m3*y3) / (m1 + m2 + m3)
= (2.3*0 + 4.0*1.0 + 9.0*2.0) / (2.3+4.0+9.0)
= (0 + 4.0 + 18.0) / 15.3
= 1.44 m (Answer)
(b) Third option, the center of mass shifts toward the topmost particle' is the correct answer.
Explanation -
when, m3 will be larger, coordinates of m3 will be considerable in respect to the coordinates of m1 and m2. Therefore, coordinate of center of mass will move towards m3.
The figure below shows a three-particle system, with masses m1 = 2.3 kg, m2 = 4.0...
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The figure below shows two masses m1=4.2 kg and m2=2.0 kg connected to separate ropes which attach to the perimeter of a uniform disk...
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between m1, which has an initial velocity v=6.9 m/s, and m2 (which
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successive collisions. The first collision between m1,
which has an initial velocity v=6.9 m/s, and m2 (which
is initially at rest) is completely inelastic. The second collision
between the combined mass m1+m2 and
m3 (which is initially at rest) is elastic. What is the
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